The area of a trapezium is 475 cm^2 and the height is 19 cm. Find the lengths of its two paallel sides if one side is 4 cm greater than the other

Jovany Clayton 2022-07-13 Answered
The area of a trapezium is 475 c m 2 and the height is 19 cm .Find the lengths of its two paallel sides if one side is 4 cm greater than the other.
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Answers (2)

gozaderaradiox5
Answered 2022-07-14 Author has 19 answers
Step 1
We know that the area of a trapezium is
A 1 2 × ( sum of parallel lines ) × ( distance between parallel lines )
Step 2
A = 475 c m 2
A = 19
Let one parallel side length x
Another parallel side length = x + 4
A = 1 2 × ( x + x + 4 ) × 19
475 = 1 2 × ( 2 x + 4 ) × 19
2 x + 4 = 2 × 475 19
2 x + 4 = 50
2 x = 46
x = 23
Second parallel side x + 4
= 23 + 4
= 27 c m
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delirija7z
Answered 2022-07-15 Author has 5 answers
Consider x cm as the smaller side of the trapeziumSo the larger parallel can be written as ( x + 4 ) c mWe know that the area of trapezium 1 2 × sum of parallel sides x heightBy substituting the values 475 = 1 2 × ( x + ( x + 4 ) ) × 19On further calculation 25 = 1 2 × ( 2 x + 4 )So we get 50 = 2 x + 4By subtraction 2 x = 50 42 x = 46
By division
x = 23 c m
So we get Larger parallel side ( x + 4 ) = 23 + 4 = 27 c m
Therefore, the length of two parallel sides is 23cm and 27cm.
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