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myntfalskj4 2022-07-16 Answered
For f ( t ) = ( 1 2 t - 3 , t e t ) what is the distance between f ( 0 ) and f ( 1 ) ?
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Answers (1)

Feriheashrz
Answered 2022-07-17 Author has 8 answers
Step 1
We have f ( t ) = ( 1 2 t - 3 , t e t ) , so:
f ( 0 ) = ( - 1 3 , 0 )
f ( 1 ) = ( - 1 , e )
So then by Pythagoras, the distance, d, between f ( 0 ) and f ( 1 ) is given by:
d 2 = ( - 1 - ( - 1 3 ) ) 2 + ( e - 0 ) 2
      = ( - 2 3 ) 2 + ( e ) 2
      = 4 9 + e 2
And so:
d = 4 9 + e 2
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