# Given: x ( t ) = 3 s i n ( t ) &#x2212;<!-- - --> 3 , y ( t )

Given: $x\left(t\right)=3sin\left(t\right)-3,y\left(t\right)=t-1$ for 0 is less than or equal to t is less than or equal to 2pi.
How do you find the position of the particle at $t=3$?
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potamanixv
Step 1
We have x and y parameterised in terms of t. We simply sub $t=3$ into these expressions for x and y to obtain the position:
$x\left(3\right)=3\mathrm{sin}\left(3\right)-3=-2.577$
Step 2
$y\left(3\right)=3-1=2$
Position is $\left(-2.6,2.0\right)$