Given: $x(t)=3sin(t)-3,y(t)=t-1$ for 0 is less than or equal to t is less than or equal to 2pi.

How do you find the position of the particle at $t=3$?

How do you find the position of the particle at $t=3$?

Dayanara Terry
2022-07-15
Answered

Given: $x(t)=3sin(t)-3,y(t)=t-1$ for 0 is less than or equal to t is less than or equal to 2pi.

How do you find the position of the particle at $t=3$?

How do you find the position of the particle at $t=3$?

You can still ask an expert for help

potamanixv

Answered 2022-07-16
Author has **15** answers

Step 1

We have x and y parameterised in terms of t. We simply sub $t=3$ into these expressions for x and y to obtain the position:

$x\left(3\right)=3\mathrm{sin}\left(3\right)-3=-2.577$

Step 2

$y\left(3\right)=3-1=2$

Position is $(-2.6,2.0)$

We have x and y parameterised in terms of t. We simply sub $t=3$ into these expressions for x and y to obtain the position:

$x\left(3\right)=3\mathrm{sin}\left(3\right)-3=-2.577$

Step 2

$y\left(3\right)=3-1=2$

Position is $(-2.6,2.0)$

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