Here is the expression: 2 ( sin 6 </msup> &#x2061;<!-- ⁡ --> x + cos

ban1ka1u

ban1ka1u

Answered question

2022-07-12

Here is the expression:
2 ( sin 6 x + cos 6 x ) 3 ( sin 4 x + cos 4 x ) + 1

Answer & Explanation

1s1zubv

1s1zubv

Beginner2022-07-13Added 17 answers

sin 4 x + cos 4 x = ( sin 2 x + cos 2 x ) 2 2 sin 2 x cos 2 x = 1 2 sin 2 x cos 2 x
sin 6 x + cos 6 x = ( sin 2 x + cos 2 x ) 3 3 sin 2 x cos 2 x ( sin 2 x + cos 2 x ) = 1 3 sin 2 x cos 2 x
Thus your expression simplifies to
2 6 sin 2 x cos 2 x 3 + 6 sin 2 x cos 2 x + 1
Which is 0, for all x
Desirae Washington

Desirae Washington

Beginner2022-07-14Added 5 answers

2 ( sin 6 x + cos 6 x ) 3 ( sin 4 x + cos 4 x ) + 1 =
= 2 ( sin 2 x + cos 2 x ) ( sin 4 x sin 2 x cos 2 x + cos 4 x ) 3 ( sin 4 x + cos 4 x ) + 1 =
= 2 ( sin 4 x sin 2 x cos 2 x + cos 4 x ) 3 ( sin 4 x + cos 4 x ) + 1 =
= 2 sin 2 x cos 2 x sin 4 x cos 4 x + 1 =
( sin 2 x + cos 2 x ) 2 + 1 = 1 + 1 = 0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?