# What is the polar form of (-1, 3)?

What is the polar form of (-1, 3)?
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Polar form is $\left(r,\theta \right)$
Step 1
$r=\sqrt{{\left(-1\right)}^{2}+{\left(3\right)}^{2}}=\sqrt{10}$
The point is in quadrant II ...
reference angle $={\mathrm{tan}}^{-1}\left(\frac{3}{1}\right)={71.565}^{o}$
Step 2
$\theta =180-71.565={108.435}^{o}$
polar form $=\left(\sqrt{10},{108.435}^{o}\right)$

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