doturitip9

2022-07-12

Solving a system of equations $x-y=17$, $\frac{4}{3}x+\frac{3}{2}y=0$

Do you have a similar question?

Jaelynn Cuevas

Expert

From the first equation by adding to both sides $y$ you get $x=17+y$. Next try to substitute obtained equation for $x$ in the second equation.

Still Have Questions?

Kaeden Hoffman

Expert

Here is an example:
$\begin{array}{rl}x+y& =5\\ 2x+3y& =10\end{array}$
There are 2 ways I might try to solve this. The first equation tells me that $x=5-y$. The second tells me that $2x+3y=10$, so plugging in for $x$, I get that $2\left(5-y\right)+3y=10-2y+3y=10+y=10$. And thus $y=0$. Then we also get (from either original equation) that $x=5$.
The other way might be to notice that $x+y=5$ is the same as $2x+2y=10$. So then I might subtract $2x+2y=10$ from $2x+3y=10$ to see that $\left(2x+3y\right)-\left(2x+2y\right)=y=0=\left(10-10\right)$. And again, $y=0$, $x=5$.
Can you apply these methods to this system?

Free Math Solver