{ <mtable columnalign="left left" rowspacing=".2em" columnspacing="1em" displaystyle=

vasorasy8 2022-07-10 Answered
{ y 2 3 0 16 y 4 96 y 2 0
the solution for the first inequality is y 3 or y 3 and the solution for the second inequality is 6 y 6 . Then for my result the solution for the system is
Then for my result the solution for the system is or 3 y 6
You can still ask an expert for help

Want to know more about Inequalities systems and graphs?

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (1)

Kroatujon3
Answered 2022-07-11 Author has 19 answers
{ y 2 3 0 16 y 4 96 y 2 0
To satisfy condition 1
y 2 3 0 y 2 3 3 y
To satisfy condition 2:
16 y 4 96 y 2 0 6 y 6
Then, to satisfy both conditions
y ( , 3 ) ( 3 , + ) ( 6 , 6 ) = ( 6 , 3 ) ( 3 , 6 )
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

You might be interested in

asked 2022-07-01
How to determine whether a system of linear inequalities has a positive solution or not?
asked 2021-03-07

Graph the feasible region for the system of inequalities
y>4x1
y2x+3

asked 2022-06-24
Is it possible to solve a linear inequality system using SVD?
I have a large linear inequality system of the form A x 0
asked 2022-06-21
Prove vertices of a simplex are affinely independent
Given that the definition of a simplex T is x R n such that x satisfies n + 1 linear inequalities: ( u k , x ) < c k for k = 1 , , n + 1 (i.e. T is the intersection of n + 1 half spaces)
If we additionally impose the condition that T must be bounded and nonempty, I was able to show that the k th vertex of T can be defined v k as the unique solution to the system ( v k , u j ) = c j for all j kThe existence of such a solution comes from the fact that any size n subset of the u k are independent. Or else we could write u k 's out as rows of a matrix and pick an arbitrarily large vector l in the nullspace. Adding that on to any existing x T would show T is unbounded since x + l T since the inequalities ( u k , x ) < c k ( u k , x + l ) < c k .
It's intuitive to me that v k 's must be affinely independent. It's also intuitive that the closure of T should be the convex hull of all the v k . In fact, I think either fact implies the other. But I'm unable to prove either of them. I was, however, able to prove that the convex hull of v k T.
Is there a simple proof that the vk are affinely independent?
asked 2022-05-29
Solve the following system of equations
{ y 2 8 x + 9 x y 6 x + 12 3 = 1 2 ( x y ) 2 + 10 x 6 y + 12 y = x + 2
asked 2022-05-21
How do you find all solutions of the following system of inequalities assuming positive and real x and y?
x y < 1
2 + x ( y 1 ) > 0
I have rearranged the first inequality to get y < 1 x and solved the second inequality for y to get
y > 1 2 x
Thus 1 x 1 2 x x 3 and the first one gives y < 1 3 .
Similarly solving the second equation for x gives x > 2 1 y so assuming that y 1 we get 1 y 2 1 y and then y 1 3 and the first one gives x < 3.
Now assuming y = 1, we get x < 1.
So the solutions found are:
x 3  AND  y < 1 3
x < 3  AND  y 1 3
x < 1  AND  y = 1
This seemed like a good method but I have missed the solution x = 1 , y < 1
How do you solve such a system to include all solutions?
asked 2022-06-14
Underdetermined system with inequality constraints
A x = b ,
where A R m × n with m < n, subject to
0 x c .
1. I would like to know if there is any way to express the feasible set for this problem analytically.
2. Is there any way to obtain any of feasible solutions in closed form?