How can I get the angle C, or better, directional vector of c which will be evenly in the middle, between the other two angles. Keep in mind that the angles might be of any value.
This old answer almost gets me were I need to be, but how can I change the final formula presented in the answer to work with non-right triangles? to work with non-right triangles?
I have found lots of results searching for this, but they don't seem to work in my case.
It looks like a good solution, but I don't know enough about trig to determine the part to change in the final formula to make it not right triangle dependant