I have three random points, O, A, B, with these I can get angles &#x03B1;<!-- α --> and &#

Blericker74 2022-07-09 Answered
I have three random points, O, A, B, with these I can get angles α and β
How can I get the angle C, or better, directional vector of c which will be evenly in the middle, between the other two angles. Keep in mind that the angles might be of any value.
This old answer almost gets me were I need to be, but how can I change the final formula presented in the answer g = arctan ( 2 tan r ) to work with non-right triangles? to work with non-right triangles?
I have found lots of results searching for this, but they don't seem to work in my case.
It looks like a good solution, but I don't know enough about trig to determine the part to change in the final formula to make it not right triangle dependant
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Answers (1)

Jaruckigh
Answered 2022-07-10 Author has 11 answers
You can use simple vector addition. Say
a ^ = O A | O A | b ^ = O B | O B | Since | a ^ | = | b ^ | = 1, c ^ = a ^ + b ^ points along the bisector of O A B
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