Fraction involving Surds Fraction involving Surds. Can anyone please show me the working out?

skynugurq7 2022-07-10 Answered
Fraction involving Surds
Fraction involving Surds. Can anyone please show me the working out?
( 6 1 ) 3 + ( 6 + 2 ) 2 3
I did this and it was incorrect:
2 3 ( 6 1 ) + 3 ( 6 + 2 ) 3 × 2 3
2 s q r t 3 ( 6 1 ) 3 + s q r t 3 ( 6 + 2 ) 2 3
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Answers (1)

talhekh
Answered 2022-07-11 Author has 15 answers
( 6 1 ) 3 + ( 6 + 2 ) 2 3 = 2 ( 6 1 ) 2 3 + ( 6 + 2 ) 2 3 put the fractions over a common denominator = 2 ( 6 1 ) + ( 6 + 2 ) 2 3 add the numerators = 2 6 2 + 6 + 2 2 3 use the distributive law to get rid of parentheses = 3 6 2 3 simple algebra = 3 2 3 2 3 setup to get rid of  3 = 3 2 3 2 3 use  x y = x y = 3 2 2 and its gone
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