Loriezon Claveria

Loriezon Claveria

Answered

2022-07-13

 

Do you have a similar question?

Recalculate according to your conditions!

Answer & Explanation

Jeffrey Jordon

Jeffrey Jordon

Expert

2022-11-07Added 2581 answers

Remove parentheses.

09y33xy2dxdy

Evaluate y33xy2dx.

Since y2 is constant with respect to x, move y2 out of the integral.

09y2y33xdxdy

By the Power Rule, the integral of x with respect to x is 12x2.

09y212x2]y33dy

Simplify the answer.

09y2(32-12(13y)2)dy

Simplify.

093y22-y418dy

Evaluate 093y22-y418dy.

 

Split the single integral into multiple integrals.

093y22dy+09-y418dy

Since 32 is constant with respect to y, move 32 out of the integral.

3209y2dy+09-y418dy

By the Power Rule, the integral of y2 with respect to y is 13y3.

3213y3]90+∫90−y418dy3213y3]09+09-y418dy

Since -1 is constant with respect to y, move -1 out of the integral.

3213y3]09-09y418dy

Since 118 is constant with respect to y, move 118 out of the integral.

3213y3]09-(11809y4dy)

By the Power Rule, the integral of y4 with respect to y is 15y5.

3213y3]09-11815y5]09

Substitute and simplify.

Evaluate 13y3 at 9 and at 0.

32((1393)-1303)-11815y5]09

Evaluate 15y5 at 9 and at 0.

32(1393-1303)-118(1595-1505)

Simplify.

-14585

The result can be shown in multiple forms.

Exact Form:

-14585

Decimal Form:

-291.6

Mixed Number Form:

-291 35


 

Still Have Questions?

Ask Your Question

Free Math Solver

Help you to address certain mathematical problems

Try Free Math SolverMath Solver Robot

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?