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malalawak44

malalawak44

Answered question

2022-07-09

If ( a k ) k = 1 converges to a R , then lim n 1 n k = 1 n a k = a

Answer & Explanation

Maggie Bowman

Maggie Bowman

Beginner2022-07-10Added 14 answers

This is proven quite straitforward: Let ϵ > 0. Scince a k a, we can choose m N , such that | a n a | ϵ 2 for all n m. Then we can choose N N , such that
1 N j = 1 m | a j | ϵ 2 .
Then, for n N
| 1 n ( j = 1 n a j ) a | 1 n j = 1 m | a j | + 1 n j = m n | a j a | ϵ 2 + n m + 1 n ϵ 2 ϵ .
However, your intuition is good, keep it in mind. The proof basically is just your intuition in formulas. (Your a k a becomes | a k a | ϵ 2 )
gorgeousgen9487

gorgeousgen9487

Beginner2022-07-11Added 4 answers

If you take b n = n, and s n as the partial sums k = 1 n a k of your original sequence, then the conditions of the Stolz-Cesaro theorem are satisfied. Then consider the limit ( 1 ) b n + 1 b n = 1 , n, so we get:
lim n s n + 1 s n = lim n a n + 1 = a
And we are done:
lim n a n + 1 = a = lim n 1 n k = 1 n a k

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