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Callum Dudley 2022-07-08 Answered
Showing that ( 1 2 p 2 sin 2 ω ) 2 + p 2 sin 2 w 1 implies 4 p 2 4
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Answers (1)

Valeria Wolfe
Answered 2022-07-09 Author has 11 answers
Since
1 1 4 p 2 sin 2 ω 2 + 4 p 4 sin 4 ω 2 + p 2 sin 2 ω
we have
0 p 2 ( 4 sin 2 ω 2 + 4 p 2 sin 4 ω 2 + sin 2 ω )
so
0 4 sin 2 ω 2 + 4 p 2 sin 4 ω 2 + sin 2 ω
so
4 sin 2 ω 2 sin 2 ω 4 p 2 sin 4 ω 2
so
4 sin 2 ω 2 sin 2 ω sin 4 ω 2 4 p 2

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