1.) Given the following equations: 3 x

woowheedr 2022-07-06 Answered
1.) Given the following equations:
3 x y = 30 5 x 3 y = 10
What are the values of x and y?
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (2)

trantegisis
Answered 2022-07-07 Author has 20 answers
You have what we call a system of two linear equations in two unknowns.
(1) 3 x y = 30 (2) 5 x 3 y = 10
There are a number of ways you can solve for the x, y values that satisfy both equations. One way you can approach this is by substitution: expressing y in equation (1) as a function of x, and "plugging" that function into into " y" in equation 2:
(1) 3 x y = 30 y = 3 x 30
(2) 5 x 3 y = 10 5 x 3 ( 3 x 30 ) = 10 5 x 9 x + 90 = 10 4 x = 80 x = 20
Now, go back to ( 1 ) and "plug in" x = 20 to solve for y:
( 1 ) x = 20 , 3 x y = 30 3 ( 20 ) y = 30 y = 30 y = 30
We have a unique solution to the system given by equations ( 1 ) and ( 2 ), namely, x = 20 , y = 30, and this corresponds to option ( a ).

We have step-by-step solutions for your answer!

vortoca
Answered 2022-07-08 Author has 2 answers
Hint:
Just substitute in your equations x and y by the given values and check the answer.

We have step-by-step solutions for your answer!

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

You might be interested in

asked 2022-07-03
How would you solve the following system of equations:
x 2 + y = 4 x + y 2 = 10
I tried defining y in terms of x and then inserting in to the second equation:
y = 4 x 2 x + ( 4 x 2 ) 2 = 10
Expand the second equation:
x + 16 8 x 2 + x 4 = 10
Rearrange the terms:
x 4 8 x 2 + x + 6 = 0
asked 2022-04-27
Solve 0.63.2x>1.42.8x.
a.x>5
b.x>10c.5>x
d.x>1.62
asked 2022-06-13
How to solve this simultaneous equations which involves exponents:
{ 2 x 2 y = 1 4 x 4 y = 5 3
Simultaneously. From the second equation I factorized to get
( 2 x + 2 y ) ( 2 x 2 y ) = 5 3
and from the first equation, since ( 2 x 2 y ) = 1, I deduced that
( 2 x + 2 y ) 1 = 5 3 ( 2 x + 2 y ) = 5 3
Now I am stuck on how to proceed.
asked 2022-05-17
Given two integer variables x and y. We are given that each integer variable x and y can't be greater than a given integer z.
The problem: We are given the proportions a and b such that a + b = 1, a = x z , and b = y z . Is it possible to reverse solve x and y?
asked 2022-09-07
Every 3 × 3 skew symmetric matrix is singular. Because this is a skew symmetric matrix, det ( A ) = det ( A T ) = det ( A ) = ( 1 ) n det ( A ), and when n is odd det ( A ) = det ( A ), so 2 det ( A ) = 0 and therefore det ( A ) = 0. As such, the answer is "False" because it is only singular when n is odd.
asked 2022-07-15
How to solve this coupled 2nd order Differential equation of a double pendulum- Runge Kutta method
θ 1 = g ( 2 m 1 + m 2 ) s i n θ 1 m 2 g s i n ( θ 1 2 θ 2 ) 2 s i n ( θ 1 θ 2 ) m 2 ( θ 2 2 l 2 + θ 1 2 l 1 c o s ( θ 1 θ 2 ) l 1 ( 2 m 1 + m 2 m 2 c o s ( 2 c o s ( 2 θ 1 2 θ 2 ) ) )
θ 2 = 2 s i n ( θ 1 θ 2 ) ( θ 1 l 1 ( m 1 + m 2 ) + g ( m 1 + m 2 ) c o s θ 1 + θ 2 2 l 2 m 2 c o s ( θ 1 θ 2 ) ) l 2 ( 2 m 1 + m 2 m 2 c o s ( 2 c o s ( 2 θ 1 2 θ 2 ) ) )
These are the equations, and How can I possibly solve this simultaneoouslt in RK4 method?
m 1 , m 2 ==masses of pendulum 1 and 2, θ 1 , θ 2 == angles formed by the pendulums, θ 1 = ω 1 , θ 2 = ω 2
asked 2022-07-03
Solve the following system of differential equations
x ˙ = 2000 3 x y 2 x y ˙ = 3 x y 6 y z ˙ = 4 y 2 z

New questions