Please explain this simple rule of logarithms to me

Right I know this one is simple and I know that I just need a push to make it sink in in my head..

I am studying control systems and in one of the tutorial examples the tutor says

Show that

$20\mathrm{log}(1/x)=-20\mathrm{log}(x)$

I know that when you have a divide or a multiply with logarithms you add them and subtract them but for my own understanding I just need someone to like slowly show me how this works..

If I take the log of the numerator I have $20\mathrm{log}(1)=0$ but I don't know where to go from here.. So do I now just take the log of the denominator and as the numerator was zero it is just minus whatever the log of the denominator is... Getting myself a bit muddled.. Thanks

Right I know this one is simple and I know that I just need a push to make it sink in in my head..

I am studying control systems and in one of the tutorial examples the tutor says

Show that

$20\mathrm{log}(1/x)=-20\mathrm{log}(x)$

I know that when you have a divide or a multiply with logarithms you add them and subtract them but for my own understanding I just need someone to like slowly show me how this works..

If I take the log of the numerator I have $20\mathrm{log}(1)=0$ but I don't know where to go from here.. So do I now just take the log of the denominator and as the numerator was zero it is just minus whatever the log of the denominator is... Getting myself a bit muddled.. Thanks