Find solution for the following system:

${x}^{\prime}={y}^{3}-4x$, ${y}^{\prime}={y}^{3}-y-3x$

As I found the three equilibrium points, $(0,0)$, $(-2,-2)$, $(2,2)$

how to find the solution for this one since they are not fully decoupled or partially decoupled?

${x}^{\prime}={y}^{3}-4x$, ${y}^{\prime}={y}^{3}-y-3x$

As I found the three equilibrium points, $(0,0)$, $(-2,-2)$, $(2,2)$

how to find the solution for this one since they are not fully decoupled or partially decoupled?