the polynomial of degree 5, P(x), has a leading coefficient 1, has roots of multiplicity 2 at x=3 and x=0, and a root of multiplicity 1 at x=-5

Alyssa Davila
2022-07-11

the polynomial of degree 5, P(x), has a leading coefficient 1, has roots of multiplicity 2 at x=3 and x=0, and a root of multiplicity 1 at x=-5

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asked 2021-01-04

Write in words how to read each of the following out loud.

a. $\{x\in {R}^{\prime}\mid 0<x<1\}$

b. $\{x\in R\mid x\le 0{\textstyle \phantom{\rule{1em}{0ex}}}\text{or}{\textstyle \phantom{\rule{1em}{0ex}}}x\Rightarrow 1\}$

c. $\{n\in Z\mid n\text{}is\text{}a\text{}factor\text{}of\text{}6\}$

d. $\{n\in Z\cdot \mid n\text{}is\text{}a\text{}factor\text{}of\text{}6\}$

asked 2021-05-13

A movie stuntman (mass 80.0kg) stands on a window ledge 5.0 mabove the floor. Grabbing a rope attached to a chandelier, heswings down to grapple with the movie's villian (mass 70.0 kg), whois standing directly under the chandelier.(assume that thestuntman's center of mass moves downward 5.0 m. He releasesthe rope just as he reaches the villian).

a) with what speed do the entwined foes start to slide acrossthe floor?

b) if the coefficient of kinetic friction of their bodies withthe floor is 0.250, how far do they slide?

asked 2021-04-06

Find the point on the plane $x+2y+3z=13$ that is closest to the point (1,1,1). How would you minimize the function?

asked 2022-03-15

Apporoaches to solve the given algebraic expression

If ${x}^{4}+{x}^{2}=\frac{11}{5}$ then what is the value of the given expression

$(\frac{x+1}{x-1}{)}^{\frac{1}{3}}+(\frac{x-1}{x+1}{)}^{\frac{1}{3}}=?$

asked 2022-06-02

The radius of a circle with area a is approximately square root of a/3. the area of a circular mouse pad is 51 square inches. estimate its radius to the nearest integer

asked 2022-05-01

Logarithmic inconsistency when integrating

Consider following integral:

$13\int \frac{1}{8x-4}dx$ (1)

By factorizing the denominator and then taking the factor outside the integral sign, it can be rewritten as

$\frac{13}{4}\int \frac{1}{2x-1}dx$ (2)

Now (1) and (2) should be equivalent, yet they evaluate into different integrals namely

$13\int \frac{1}{8x-4}dx=\frac{13}{8}\mathrm{ln}|8x-4|+C$ (1a)

$\frac{13}{4}\int \frac{1}{2x-1}dx=\frac{13}{8}\mathrm{ln}|2x-1|+C$ (2a)

Since $\left(1\right)\equiv \left(2\right)$ , then (1a) and (2a) should be equivalent as well, which reduces to

$\mathrm{ln}|8x-4|=\mathrm{ln}|2x-1|$

which clearly isn't true. What am I missing here?

asked 2022-05-11

When Barry was traveling in Europe, he noticed that the temperature said 12°C, but wasn't sure of the weather because he was familiar with degrees Fahrenheit. What is the temperature to the nearest degree in degrees Fahrenheit?