# What is the polar form of <mstyle displaystyle="true"> ( 11 ,

What is the polar form of $\left(11,55\right)$ ?
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Jaelynn Cuevas
Step 1
$\mathrm{tan}\left(\theta \right)=\frac{\text{opposite}}{\text{adjacent}}\to \theta =\text{arctan}\left(\frac{\text{opposite}}{\text{adjacent}}\right)$
$\theta =\text{arctan}\left(\frac{55}{11}\right)=\text{arctan}\left(5\right)\approx 1.3734\left(\text{}radians\right)\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}{78.69}^{\circ }$
By Pythagorean Theorem:
$r=\sqrt{{11}^{2}+{55}^{2}}\approx 56.09$