The position vector r(t) = <<lnt, 1/t^2, t^4>> describes the path of an object moving in space. (a) Find the velocity vector, speed, and acceleration vector of the object. (b) Evaluate the velocity vector and acceleration vector of the object at the given value of t = sqrt3

sagnuhh

sagnuhh

Answered question

2020-12-29

The position vector r(t)=lnt,1t2,t4 describes the path of an object moving in space.
(a) Find the velocity vector, speed, and acceleration vector of the object.
(b) Evaluate the velocity vector and acceleration vector of the object at the given value of t=3

Answer & Explanation

Caren

Caren

Skilled2020-12-30Added 96 answers

a) Velocity vector is the derivative of position vector. So to find velocity vector, differentiate position vector with respect to t. We get v(t)=lnt,1t2,t4
Now speed is the magnitude of velocity vector. That is,
Speed = ||v||
=(1t)2+(2t3)2+(4t3)2
=1t2+4t6+16t6
=t4+4+16t12t6
=16t12+t4+4t3
Acceleration vector is the derivative of the velocity vector.So to find acceleration vector, differentiate velocity vector with respect to t. We get,
a(t)=1t2,2(3t4),4(3t2)=1t2,6t4,12t2
b) Put t=3 in the velocity vector, we get
v(3)=13,2(3)3,4(3)3=13,233,123
Put t=3 ⎯ in the acceleration vector, we get
a(3)=1(3)2,63,12(3)2=13,69,12(3)=13,23,36

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