We are given a ratio: g ( x ) </mrow> f

Rapsinincke

Rapsinincke

Answered question

2022-07-02

We are given a ratio:
g ( x ) f ( x )
where:
g ( x ) R +
f ( x ) N f ( x ) 2
So g ( x ) returns values in [ 0 , + ] while f ( x ) returns values in { 2 , 3 , 4 , }.

I am looking for a confirmation about a very simple question: if I maximize g ( x ) f ( x ) , do I also maximize g ( x ) f ( x ) 1 in this very particular case?

Answer & Explanation

Tamia Padilla

Tamia Padilla

Beginner2022-07-03Added 16 answers

Of course you do not.

An example is g ( x ) = x 2 100 x + 10000, and f ( x ) = max { x , 2 } .. [Sorry for not finding a nice example]

In one case you have minimum is somewhere around 76-77, in the other one 79-80.

EDIT: I see you wanted to maximize, I did minimize. But the reason why it doesn't hold is the same.
ntaraxq

ntaraxq

Beginner2022-07-04Added 3 answers

If I interpret your question correctly, this depends on f ( x ) and g ( x ), e.g.:

if f ( x ) is constant then g ( x ) f ( x ) = c g ( x ) (c being a constant), so it is maximized at the same x (obviously).

if e.g. g ( x ) is constant and f ( x ) is not and there is a x 0 such that f ( x 0 ) 1 = f ( x ), then clearly(well, by substitution) this x 0 is the maximum. Example: 1 x + 2 is maximal for x = 1 whereas 1 x + 2 1 is maximal for x = 0. ( is the ceiling function that returns the next larger integer for any real number)

Also, g ( x ) f ( x ) 1 is not defined if f ( x ) = 1.

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