Augustus Acevedo
2022-07-03
Answered

How do you solve $19.4<-x+5.6$ ?

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Kaylie Mcdonald

Answered 2022-07-04
Author has **19** answers

Step 1

Let's start by subtracting 5.6 from both sides. Doing this, we get

$13.8<-x$

Now, let's divide both sides by -1. Remember, when dividing by a negative, the direction of the inequality flips. We get

$-13.8>x$

Let's start by subtracting 5.6 from both sides. Doing this, we get

$13.8<-x$

Now, let's divide both sides by -1. Remember, when dividing by a negative, the direction of the inequality flips. We get

$-13.8>x$

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Identify, whether $x\u20137>-2{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}x>5$ are equivalent inequalities or not equivalent?

asked 2022-03-23

Solve using any algebraic method.

$a-\frac{1}{4}c=3$

$c+4a=4$

Select the correct choice below and ,if necessary,fill in the answer box to complete your choice.

A. The solution is ____ . (Type an ordered pair.)

B. THere are infinitely many solutions.The solution set is$(x,y)\mid a-\frac{1}{4}c=3$ or $c+4a=4$

C. There is no solution.

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Classify the linear equation for each system:

a) Line 1: $y=\frac{-1}{4}x-4$

Line 2: $x+4y=-16$

b) Line 1: $y=-2x+6$

Line 2: $y=\frac{1}{2}x+1$

c) Line 1: $y=\frac{2}{3}x+3$

Line 2: $y=\frac{2}{3}x+4$

I) This system of equations is:

1) consistent independent

2) consistent dependent

3) inconsistent

II) This means the system has:

1) a unique solution

2) no solution

3) infinitely many solutions

a) Line 1: $y=\frac{-1}{4}x-4$

Line 2: $x+4y=-16$

b) Line 1: $y=-2x+6$

Line 2: $y=\frac{1}{2}x+1$

c) Line 1: $y=\frac{2}{3}x+3$

Line 2: $y=\frac{2}{3}x+4$

I) This system of equations is:

1) consistent independent

2) consistent dependent

3) inconsistent

II) This means the system has:

1) a unique solution

2) no solution

3) infinitely many solutions

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