ban1ka1u
2022-07-04
Answered

How do you evaluate 8P3?

You can still ask an expert for help

bap1287dg

Answered 2022-07-05
Author has **13** answers

Explanation:

The permutation formula is $\text{}}_{n}{P}_{r}=\frac{n!}{(n-r)!$. Since $n=8$ and $r=3$. We can just substitute values and solve:

$\text{}}_{n}{P}_{r}=\frac{n!}{(n-r)!}=\frac{8!}{(8-3)!}=\frac{8\cdot 7\cdot 6\cdot \overline{)5\cdot 4\cdot 3\cdot 2\cdot 1}}{\overline{)5\cdot 4\cdot 3\cdot 2\cdot 1}$

$8\cdot 7\cdot 6=336$

The permutation formula is $\text{}}_{n}{P}_{r}=\frac{n!}{(n-r)!$. Since $n=8$ and $r=3$. We can just substitute values and solve:

$\text{}}_{n}{P}_{r}=\frac{n!}{(n-r)!}=\frac{8!}{(8-3)!}=\frac{8\cdot 7\cdot 6\cdot \overline{)5\cdot 4\cdot 3\cdot 2\cdot 1}}{\overline{)5\cdot 4\cdot 3\cdot 2\cdot 1}$

$8\cdot 7\cdot 6=336$

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