If the chance of an event was 1 <mrow class="MJX-TeXAtom-ORD"> / </mrow> 128 and

Caleb Proctor 2022-07-02 Answered
If the chance of an event was 1 / 128 and increased by 20%, what is the new chance?
So I have something that has a 1/128 chance of occurring, let's say. Suddenly, the chances of that thing happening are increased by 20%. How is that fraction written? Would you multiply 1/128 by 6/5 (yielding 3/320), or would you take 128, multiply it by 4/5, and then invert it (1/102)?
This isn't for homework, I'm merely curious.
Thank you
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Answers (2)

Mateo Carson
Answered 2022-07-03 Author has 15 answers
Multiplying by 6 / 5 = 1.2 is the correct approach. This increases a value by 20 %. Multiplying by 4 / 5 decreases a value by 20 %, but inverting that is not the same as increasing by 20 %. It results in multiplying by 5 / 4, which is an increase of 25 %. On top of that, 128 4 5 = 102.4 , not 102

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ddcon4r
Answered 2022-07-04 Author has 4 answers
The first approach is correct.
Initial p = 1 128 , you need to increase p by 20 %
Note
Since p = 1 128 , i.e. in the form of a fraction, it is possible to obtain the correct result by manipulating its denominator only, but then you would need to divide the denominator by 1.2i.e. multiply it by 5 6

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