${x}^{3}>x$

desertiev5
2022-07-01
Answered

Solve the following inequalities:

${x}^{3}>x$

${x}^{3}>x$

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Kayley Jackson

Answered 2022-07-02
Author has **16** answers

${x}^{3}>x$

${x}^{3}-x>0$

$x({x}^{2}-1)>0$

$x(x-1)(x+1)>0$

$x(x-1)(x+1)>0$

$x(x-1)(x+1)=0$

$x=0;x=1;x=-1$

$x=-10:(-10)(-11)(-9)>0$

$(-)(-)(-)\text{\u29f8}>0$

$x=\frac{1}{2}:\frac{1}{2}(-\frac{1}{2})(\frac{3}{2})>0$

$(+)(-)(+)\text{\u29f8}>0$

$x=-\frac{1}{2}:-\frac{1}{2}:-\frac{1}{2}(-\frac{3}{2})(\frac{1}{2})>0$

$(-)(-)(+)>0$

${x}^{3}-x>0$

$x({x}^{2}-1)>0$

$x(x-1)(x+1)>0$

$x(x-1)(x+1)>0$

$x(x-1)(x+1)=0$

$x=0;x=1;x=-1$

$x=-10:(-10)(-11)(-9)>0$

$(-)(-)(-)\text{\u29f8}>0$

$x=\frac{1}{2}:\frac{1}{2}(-\frac{1}{2})(\frac{3}{2})>0$

$(+)(-)(+)\text{\u29f8}>0$

$x=-\frac{1}{2}:-\frac{1}{2}:-\frac{1}{2}(-\frac{3}{2})(\frac{1}{2})>0$

$(-)(-)(+)>0$

Jeffrey Jordon

Answered 2022-07-07
Author has **2581** answers

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