What is the polar form of $(-4,6)$ ?

Rebecca Villa
2022-07-02
Answered

What is the polar form of $(-4,6)$ ?

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Zane Barry

Answered 2022-07-03
Author has **5** answers

Step 1

For any point $P(a,b)$ in the Cartesian plane, we can convert it to polar form $(r,\vartheta )$ using the following formulae

$r=\sqrt{{a}^{2}+{b}^{2}}$

$\vartheta =\mathrm{arctan}\left(\frac{b}{a}\right)$

$\therefore r=\sqrt{-{4}^{2}+{6}^{2}}=2\sqrt{13}$

$\therefore (-4,6)=(2\sqrt{13},-0.923)$

For any point $P(a,b)$ in the Cartesian plane, we can convert it to polar form $(r,\vartheta )$ using the following formulae

$r=\sqrt{{a}^{2}+{b}^{2}}$

$\vartheta =\mathrm{arctan}\left(\frac{b}{a}\right)$

$\therefore r=\sqrt{-{4}^{2}+{6}^{2}}=2\sqrt{13}$

$\therefore (-4,6)=(2\sqrt{13},-0.923)$

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