# What is the polar form of <mstyle displaystyle="true"> ( - 4 ,

What is the polar form of $\left(-4,6\right)$ ?
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Step 1
For any point $P\left(a,b\right)$ in the Cartesian plane, we can convert it to polar form $\left(r,\vartheta \right)$ using the following formulae
$r=\sqrt{{a}^{2}+{b}^{2}}$
$\vartheta =\mathrm{arctan}\left(\frac{b}{a}\right)$
$\therefore r=\sqrt{-{4}^{2}+{6}^{2}}=2\sqrt{13}$
$\therefore \left(-4,6\right)=\left(2\sqrt{13},-0.923\right)$