Get rid of the square roots of the denominator: <mstyle displaystyle="true" scriptlevel="0">

Ryan Robertson 2022-07-02 Answered
Get rid of the square roots of the denominator: 1 7 2 5 + 3
I squared the whole denominator, but that didn't help.
Also I searched for a propriety or identity like A 2 B 2 , but I didn't see one that could fit. Any help is appreciated.
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Answers (2)

iskakanjulc
Answered 2022-07-03 Author has 18 answers
1 7 2 5 + 3 = 1 7 2 5 + 3 7 2 5 3 7 2 5 3 = 7 2 5 3 ( 7 2 5 ) 2 3 = 7 2 5 3 4 ( 6 35 ) 6 + 35 6 + 35 = ( 7 2 5 3 ) ( 6 + 35 ) 4
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tripes3h
Answered 2022-07-04 Author has 5 answers
To get rid of the square roots of the denominator, you may use a 2 b 2 = ( a + b ) ( a b )
1 7 2 5 + 3 = 7 2 5 3 ( 7 2 5 ) 2 3 = 7 2 5 3 7 4 35 + 20 3 = 7 2 5 3 24 4 35 = ( 7 2 5 3 ) ( 24 + 4 35 ) 24 2 16 35 = ( 7 2 5 3 ) ( 24 + 4 35 ) 16 = 24 3 20 5 16 7 4 105 16 = 6 3 5 5 4 7 105 4
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