How to solve this system of linear inequalities? <mtable columnalign="right left right left righ

Sylvia Byrd

Sylvia Byrd

Answered question

2022-07-01

How to solve this system of linear inequalities?
θ 1 + θ 2 0 2 θ 1 + k θ 2 0 θ 1 + 3 θ 2 0

Answer & Explanation

cefflid6y

cefflid6y

Beginner2022-07-02Added 13 answers

θ 1 + θ 2 0 ( i )
and θ 1 + 3 θ 2 0 θ 1 3 θ 2 0 ( i i )
From ( i ) and ( i i ),
θ 1 + θ 2 θ 1 3 θ 2 0
( θ 2 0 θ 2 0)
Now,
θ 1 + θ 2 0 θ 1 θ 2 0
( θ 1 0)
Do similarly with 2 θ 1 + k θ 2 0
ddcon4r

ddcon4r

Beginner2022-07-03Added 4 answers

Calling
v 1 = ( 1 , 1 ) v 2 = ( 2 , k ) v 3 = ( 1 , 3 )
now if v 2 = λ 1 v 1 + λ 2 v 3 with ( λ 1 , λ 2 ) 0 then the inequality system has non trivial solution otherwise the solution is θ 1 = θ 2 = 0. In the present case we have
λ 1 = 6 k 2 0 λ 2 = 2 k 2 0
so the condition for non trivial solution is k 2
Now assuming that the solution is non trivial and calling Θ = ( θ 1 , θ 2 ), this solution should verify
v 1 Θ 0 v 2 Θ 0 v 3 Θ 0
which is verified for
Θ ( μ 1 , μ 3 ) = μ 1 v 1 + μ 3 v 3 0
with μ i 0 , i = 1 , 3

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?