Evaluate this trig limit without L'Hospital: <munder> <mo movablelimits="true" form="prefix

Cory Patrick 2022-07-01 Answered
Evaluate this trig limit without L'Hospital: lim x   0 x tan ( π ( 1 x ) 2 )
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Answers (1)

Mateo Barajas
Answered 2022-07-02 Author has 13 answers
Using some trig identities, we have
x tan ( π 2 π x 2 ) = x cot ( π x 2 ) = x cos ( π x 2 ) sin ( π x 2 ) = 2 π cos ( π x 2 ) ( sin ( π x 2 ) π x 2 ) 1
And recall how to do limits of the form sin ( u ) u .
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