Consider the non-triangle shown below that has side lenghts of 1.6, 1.751 and 2.6 cm and interior angle measures of 0.72, alpha and beta degrees.What is value of alpha and beta01510101641.png

Consider the non-triangle shown below that has side lenghts of 1.6, 1.751 and 2.6 cm and interior angle measures of 0.72, alpha and beta degrees.What is value of alpha and beta01510101641.png

Question

Consider the non-triangle shown below that has side lenghts of 1.6, 1.751 and 2.6 cm and interior angle measures of 0.72, alpha and beta degrees.
What is value of alpha and beta
image

Answers (1)

2021-02-01
According to sine law:
\(\displaystyle\frac{{{\sin{{A}}}}}{{a}}=\frac{{{\sin{{B}}}}}{{b}}=\frac{{{\sin{{C}}}}}{{c}}\)
Thus, (sin alpha)/1.6=(sin 41.253^@)/1.751ZSK
\(\displaystyle{\sin{\alpha}}=\frac{{{1.6}\cdot{\sin{{41.253}}}^{\circ}}}{{1.751}}\)
\(\displaystyle{\sin{\alpha}}={0.60252}\)
\(\displaystyle\therefore\alpha={37.051}^{\circ}\)
Now, using triangle property
\(\displaystyle{A}+{B}+{C}={180}^{\circ}\)
\(\displaystyle\alpha+\beta+{41.253}={180}^{\circ}\)
\(\displaystyle{37.051}+\beta={180}^{\circ}-{41.253}^{\circ}\)
\(\displaystyle\beta={138.747}-{37.051}\)
\(\displaystyle\therefore\beta={101.696}^{\circ}\)
Therefore,
\(\displaystyle\alpha={37.051}^{\circ}\)
\(\displaystyle\beta={101.696}^{\circ}\)
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