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hawatajwizp 2022-06-26 Answered
How to calculate the integral 0.5 1 1 2 x x 2 ?
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Answers (2)

Marlee Guerra
Answered 2022-06-27 Author has 25 answers
Note that
2x-x2=1-(1-2x+x2)=1-(1-x)2
Now you can use a trig substitution.
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minwaardekn
Answered 2022-06-28 Author has 6 answers
Given 0.5 1 1 2 x x 2 d x
= 1 1 ( x 1 ) 2 d x
Apply u substitution u=x-1
1 1 u 2 d u = arcsin ( u ) = arcsin ( x 1 )
Now apply the boundaries
= [ arcsin ( x 1 ) ] 0.5 1 = π 6
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