What is the surface area of the solid created by revolving f ( x ) = 2 x <m

skylsn

skylsn

Answered question

2022-06-27

What is the surface area of the solid created by revolving
f ( x ) = 2 x 3 2 x , x [ 2 , 4 ] around the x axis?

Answer & Explanation

Angelo Murray

Angelo Murray

Beginner2022-06-28Added 23 answers

Explanation:
The area is given by the following integral:
A = 2 4 2 π f ( x ) d x = 2 π 2 4 ( 2 x 3 2 x ) d x =
2 π [ x 4 2 x 2 ] 2 4 = 2 π ( 4 4 2 4 2 2 4 2 + 2 2 ) =
2 π 108 = 216 π

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