A quadratic function has its vertex at the point (1,6). The function passes through the point (-2, -3). Find the quadratic and linear coefficients and the constant team of the function. -The quadratic coefficients is -The linear coefficients is -The constant term is

Cabiolab 2020-12-22 Answered
A quadratic function has its vertex at the point (1,6). The function passes through the point (-2, -3). Find the quadratic and linear coefficients and the constant team of the function.
-The quadratic coefficients is
-The linear coefficients is
-The constant term is
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Expert Answer

Bella
Answered 2020-12-23 Author has 81 answers

Standard vertex form of quadratic function is
y=a(xh)2+k
Where point (h,k) is vertex point.
vertex point is (1,6)
Substitute this point in standard vertex form
y=a(x1)2+6
=a(x1)2+6(1)
Also function pass through point (−2,−3).
3=a(21)2+6
3=a(3)2+6
3=a9+6
9a=36
9a=9
a=99
=-1
Substitute 'a' value in equation (1)
y=(1)(x1)2+6
=(x2+12x)+6
=x2+2x1+6
=x2+2x+5
Hence quadratic function is y=x2
Where
Quadratic coefficient =−1
Linear coefficient=2
Constant term=x2+2x+5

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