 # Simultaneous Equations <mtable displaystyle="true"> <mlabeledtr> <mtd id="mjx-eqn-1 Semaj Christian 2022-06-27 Answered
Simultaneous Equations
$\begin{array}{}\text{(1)}& 19s+12t=82\end{array}$
$\begin{array}{}\text{(2)}& 5s+4t=30\end{array}$
The point of the exercise is to find the values of t and s.
-So what I've done is label the first equation 1 and the second equation 2, as normal.
-Then I multiplied equation 2 by 3 to make the value of t the same on both equations and labelled this, new equation, equation 3:
$\begin{array}{}\text{(3)}& 15s+12t=90\end{array}$
-Then I took equation 3 from equation 2 to breaking it down to find the value of s.
(3) - (2)
$4s=8$
$s=2$
-So, at this point I have worked out that s=2.
-The problem, for me, is when I substitute the value of s back into equation 1. the value of t is a recurring number of 6.
-Have i done something wrong?
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$4s=-8$
$s=-2$
Put value in equation (1) or (2)
$t=10$

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