# Solve the quadratic equation for all values of x in simpls form 4(x+8)^2=4

Solve the quadratic equation for all values of x in simpls form
$$\displaystyle{4}{\left({x}+{8}\right)}^{{2}}={4}$$

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pattererX

Dividing ot sides by 4
$$\displaystyle\frac{{{4}{\left({x}+{8}\right)}^{{2}}}}{{4}}=\frac{{4}}{{4}}$$
$$\displaystyle{\left({x}+{8}\right)}^{{2}}={1}$$
Taking square root on both sides
$$\displaystyle\sqrt{{{\left({x}+{8}\right)}^{{2}}}}=\sqrt{{1}}$$
$$x+8=+-1$$
When $$x+8=1$$
so, $$x=1-8$$
$$x=-7$$
When $$x+8=-1$$
so, $$x=-1-8$$
$$x=-9$$
The solution are $$x=-7$$ and $$x=-9$$