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Brunton39

Brunton39

Answered question

2022-06-24

Is 1 ( x + 3 ) 2 strictly greater than 2 x - 3 ?

Answer & Explanation

luisjoseblash2

luisjoseblash2

Beginner2022-06-25Added 16 answers

Step 1
If it was, then the answer to "For which values of x the following disequality holds?"
1 ( x + 3 ) 2 - 2 x - 3 > 0
Should be "Always". Let's check it. Make the fractions have a common denominator, and you'll end up with x - 3 ( x + 3 ) 2 ( x - 3 ) - 2 ( x + 3 ) 2 ( x + 3 ) 2 ( x - 3 ) > 0
Step 2
Now sum the numerator:
( x - 3 ) - 2 ( x + 3 ) 2 = x - 3 - 2 ( x 2 + 6 x + 9 ) =
= x - 3 - 2 x 2 - 12 x - 18 =
= - 2 x 2 - 11 x - 21 = - ( 2 x 2 + 11 x + 21 )
Step 3
SInce 2 x 2 + 11 x + 21 has a negative discriminant, it has no solution, and so it is always positive. So, the fraction becomes - 2 x 2 + 11 x + 21 ( x + 3 ) 2 ( x - 3 ) .
and we know that 2 x 2 + 11 x + 21 and ( x + 3 ) 2 are always positive (the latter being a square). So, the sign of the whole fraction depends on the sign of x - 3 , which obviously is positive after 3 and negative before. Since there is a minus before the whole fraction, we have that the expression is positive only before 3, and so the answer is no:
1 ( x + 3 ) 2 is not always greater than 2 x - 3 , but only before 3.

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