Let ( A , <mi mathvariant="fraktur">m <mo mathvariant="fraktur" stretchy="false">) be a

Hailie Blevins

Hailie Blevins

Answered question

2022-06-21

Let ( A , m ) be a local Noetherian ring and let x 1 , , x d be a system of parameters, i.e. m = ( x 1 , , x d ). Then
dim A / ( x 1 , , x i ) = d i
i = 1 , , d
I know just a few basic facts about dimension theory. I think I can prove the inequality via Krull's Hauptidealsatz in this way: the maximal ideal of A / ( x 1 , , x i ) is
m i := ( x i + 1 ¯ , , x d ¯ ) .
So it must be h t ( m i ) d i.
But how to prove the other inequality? I think I should do it by induction, but I cannot understand how to begin. So, if what I said so far is right, my question is: how can I prove that
dim A / ( x 1 ) d 1 ?

Answer & Explanation

EreneDreaceaw

EreneDreaceaw

Beginner2022-06-22Added 20 answers

Your proof for the 1st part is not true: x 1 , , x d being system of parameters does not mean m = ( x 1 , , x d ) ,, So ( x i + 1 ¯ , , x d ¯ ) isn't necessarily the maximal ideal of A / ( x 1 , , x i ) .

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