The graph of the quadratic function y = ( x &#x2212;<!-- − --> h )

Poftethef9t

Poftethef9t

Answered question

2022-06-21

The graph of the quadratic function y = ( x h ) 2 + k passes through ( 3 , 7 ) and ( 4 , 11 ). The axis of symmetry is the graph is x = 2. How can I find the y-intercept of the graph? I know that it is the value of k(the minimum value of the function) but how could I find it?

Answer & Explanation

timmeraared

timmeraared

Beginner2022-06-22Added 22 answers

Consider
y = ( x h ) 2 + k
Passes through     ( 3 , 7 )     and     ( 4 , 11 )
7 = ( 3 h ) 2 + k       and       11 = ( 4 h ) 2 + k
Solving these 2 simultaneously
h = 3 2 ,   k = 19 4
y = ( x 3 2 ) 2 + 19 4
Llubanipo

Llubanipo

Beginner2022-06-23Added 9 answers

Y-intercept is the value of y at which graph touches y-axis(x=0). In the given case, y-intercept can be k only if h=0. You can compute it by puttting x=0 in the equation.

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