I seek your help on this question. <munder> <mo movablelimits="true" form="prefix">lim <

misurrosne

misurrosne

Answered question

2022-06-22

I seek your help on this question.
lim x ( 9 x 6 + 7 x 3 + 5 x 9 x 6 + 6 x 2 + 3 x )

Answer & Explanation

pheniankang

pheniankang

Beginner2022-06-23Added 22 answers

We know that, by asymptotic relations:
( 1 + f ( x ) ) α α f ( x ) when f ( x ) 0
One can write:
lim x ( 9 x 6 + 7 x 3 + 5 x 9 x 6 + 6 x 2 + 3 x ) = lim x 9 x 6 + 6 x 2 + 3 x ( 9 x 6 + 7 x 3 + 5 x 9 x 6 + 6 x 2 + 3 x 1 ) = lim x 9 x 6 + 6 x 2 + 3 x ( 9 x 6 + 6 x 2 + 3 x + ( 7 x 3 6 x 2 ) 9 x 6 + 6 x 2 + 3 x 1 ) = lim x 9 x 6 + 6 x 2 + 3 x ( 1 + 7 x 3 6 x 2 9 x 6 + 6 x 2 + 3 x 1 ) lim x 3 x 3 ( 1 + 7 x 3 9 x 6 1 ) lim x 3 x 3 1 2 7 9 x 3 = 7 6
So, the limit is 7 6

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