Antiderivative of d y </mrow> d x </mrow> </mfrac>

Roland Manning

Roland Manning

Answered question

2022-06-17

Antiderivative of d y d x
Find the antiderivative of d y d x = e 2 x x and y = 5 when x = 0.
the antiderivative formula is e k x d x = 1 k e k x + c.
I did it, d y d x = e 2 x x and y = 5 when x = 0.
d y d x = 1 2 e 2 x + c but the right answer is y = 1 2 ( e 2 x x 2 + 9 )

Answer & Explanation

Rebekah Zimmerman

Rebekah Zimmerman

Beginner2022-06-18Added 32 answers

Step 1
You made two major errors. First, you found the antiderivative only of the exponential term and forgot all about the x term: you should have got y = 1 2 e 2 x x 2 2 + c ..
Note that this is y, not dy/dx.
Step 2
Secondly, you found all of the antiderivatives, but the problem requires you to find the specific antiderivative such that y = 5 when x = 0. Take the corrected general antiderivative,
y = 1 2 e 2 x x 2 2 + c ,,
and substitute y = 5 and x = 0 to get
5 = 1 2 e 0 0 2 + c = 1 2 + c ;;
clearly we must have c = 5 1 2 = 9 2 ,, and the unique antiderivative that satisfies the extra condition is y = 1 2 e 2 x x 2 2 + 9 2 = 1 2 ( e 2 x x 2 + 9 ) .

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