I am not that familiar in proving measurability of a function. The definition I know is that the pre

varitero5w

varitero5w

Answered question

2022-06-16

I am not that familiar in proving measurability of a function. The definition I know is that the preimage of measurable sets has to be measurable again. But how to prove that seems difficult to me at the first glance. I do have the following exercise: Let ( B t ) be a Brownian motion on ( Ω , A , P ) with continuous trajectories/paths. Consider the product space
( [ 0 , ) , B [ 0 , ) , λ ) ( Ω , A , P )
where λ is the Lebesgue measure. Show that the mapping ( t , ω ) ( B t ( ω ) )( t 0) defined from that space to ( R [ 0 , ) , B R [ 0 , ) ) is measurable. How can I prove this? I think the continuity is important, but I dont know how to involve it. Any help is appreciated.

Answer & Explanation

Arcatuert3u

Arcatuert3u

Beginner2022-06-17Added 30 answers

Approximate B ( t , ω ) by the sequence of simple processes { B ( n ) ( t , ω ) = B ( 2 n 2 n t , ω ) }. It is easy to see that ( t , ω ) B ( n ) ( t , ω ) is B [ 0 , ) A -measurable and B ( n ) B pointwise as n ( B is continuous). Thus, B is also measurable as the limit of measurable functions.

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