 # Write the complex number in standart form 6i^2-8i^3 naivlingr 2020-12-07 Answered
Write the complex number in standart form $6{i}^{2}-8{i}^{3}$
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A complex number z is of the form x+iy (standard form) , where x and y are real numbers (called the real and imaginary parts of z). The manipulation with complex numbers follow the same rules as for real numbers , except that the symbol i satisfies ${i}^{2}=-1$. (i is square root of -1).
The simplification of the given expression:
${i}^{2}=-{1}^{3}$
$z=6{i}^{2}-8i$
$=6\cdot \left(-1\right)-8{i}^{i}$
=-6-8*(-1)i
Given the complex number z=x+iy (with x an d y both real), its complex conjugate z(bar) (see above) is defined to be the complex number x-iy.
z=x+iy (x,y real)
the complex conjugate
$\stackrel{―}{z}=x-iy$
Given
z=-6+8i
Therefore, its complex conjugate is
$\stackrel{―}{z}=-6-8i$