Help with simplification of a rational expression (with fractional powers) Can you please help me

Brunton39

Brunton39

Answered question

2022-06-13

Help with simplification of a rational expression (with fractional powers)
Can you please help me see what I don't see yet. Here's a problem from a high school textbook (ISBN 978-5-488-02046-7 p.9, #1.029):
( a 1 / m a 1 / n ) 2 4 a ( m + n ) / m n ( a 2 / m a 2 / n ) ( a m + 1 m + a n + 1 n )
Here's my try at it:
( a 1 / m a 1 / n ) ( a 1 / m a 1 / n ) 4 a ( 1 / m ) + ( 1 / n ) ( a 1 / m a 1 / n ) ( a 1 / m + a 1 / n ) a ( a 1 / m + a 1 / n )
...which is
( a 1 / m a 1 / n ) 4 a ( 1 / m ) + ( 1 / n ) a ( a 1 / m + a 1 / n ) 2
Wolfram Alpha's simplify stops here, too. I don't see where to go from here. The final form, according to the book, is this:
1 a ( a 1 / m a 1 / n )
How did they do it?

Answer & Explanation

Marlee Guerra

Marlee Guerra

Beginner2022-06-14Added 25 answers

After checking the older edition of the book, I'm quite sure that the original problem looked like this:
( a 1 / m a 1 / n ) 2 + 4 a ( m + n ) / m n ( a 2 / m a 2 / n ) ( a m + 1 m + a n + 1 n )
Now we have:
( a 1 / m a 1 / n ) 2 + 4 a ( m + n ) / m n = ( a 1 / m + a 1 / n ) 2
( a 2 / m a 2 / n ) ( a m + 1 m + a n + 1 n ) = a ( a 1 / m a 1 / n ) 2 ( a 1 / m + a 1 / n ) 2
Finally we get:
( a 1 / m a 1 / n ) 2 + 4 a ( m + n ) / m n ( a 2 / m a 2 / n ) ( a m + 1 m + a n + 1 n ) = 1 a ( a 1 / m a 1 / n )
abbracciopj

abbracciopj

Beginner2022-06-15Added 4 answers

( a 1 / m a 1 / n ) 4 a ( 1 / m ) + ( 1 / n ) a ( a 1 / m + a 1 / n ) 2 = ( a 1 / m a 1 / n ) 4 a ( 1 / m ) + ( 1 / n ) ( a 1 / m a 1 / n ) a ( a 1 / m + a 1 / n ) 2 ( a 1 / m a 1 / n )
So one need simplify:
( a 1 / m a 1 / n ) 2 4 a ( 1 / m ) + ( 1 / n ) ( a 1 / m + a 1 / n ) 2 = 4 ( a 2 / m + a 2 / n 2 a 1 / m + 1 / n ) a ( 1 / m ) + ( 1 / n ) ( a 1 / m + a 1 / n ) 2 = 4 ( a 3 / m + 1 / n + a 3 / n + 1 / m 2 a 2 / m + 2 n ) ( a 1 / m + a 1 / n ) 2
This is the nearest simplification that I could reach. It cannot be simplified as 1 unless
4 ( a 3 / m + 1 / n + a 3 / n + 1 / m 2 a 2 / m + 2 n ) = ( a 1 / m + a 1 / n ) 2

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