Why Doesn't 2 <mrow class="MJX-TeXAtom-ORD"> 1 <mrow class="MJX-TeXAtom

pokoljitef2

pokoljitef2

Answered question

2022-06-14

Why Doesn't 2 1 / n = 1 / ( 2 n )
Take 2 1 / n . Since 1 / n can be simplified as n 1 , the original term can become 2 n 1 . The exponents can then be multiplied to result in 2 n which is 1 / ( 2 n ). However it is obvious that
2 1 / n 1 / ( 2 n )
because the first item approaches 1 as n but the second item approaches 0. What is wrong with the logic I used to simplify the first into the second that causes this discrepancy?

Answer & Explanation

Josie123

Josie123

Beginner2022-06-15Added 16 answers

Exponents multiply in the sense that
( a b ) c = a b c .
They do not multiply in the sense that
a ( b c ) a b c .
tr2os8x

tr2os8x

Beginner2022-06-16Added 10 answers

The order in which you do the operations is vital here. Unlike addition and multiplication, exponentiation is not associative:
a ( b c ) ( a b ) c
for "most" values of a, b and c
It is true that 2 1 / n = 2 n 1 , but that's because 2 n 1 means 2 ( n 1 ) . As you saw for yourself, 2 ( n 1 ) is not the same thing at all as ( 2 n ) 1

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