Antiderivative of infinitely often differentiable function Define interval I = ( 0

arridsd9

arridsd9

Answered question

2022-06-14

Antiderivative of infinitely often differentiable function
Define interval I = ( 0 , 1 ), C ( I ) as a ring of infinitely often differentiable functions from I to R , and C C ( I ) C ( I ) an ideal of functions having compact support. Set d : C ( I ) C ( I ) and d ¯ : C C ( I ) C C ( I ) a usual differentiation.
Is it true that Im ( d ) = C ( I ) and Im ( d ¯ ) = C C ( I )? In other words, is it true that antiderivative F of f C ( I ) also lies in C ( I ) and same for C C ( I )? If not, how can one describe Im ( d ) and Im ( d ¯ )?

Answer & Explanation

Quinn Everett

Quinn Everett

Beginner2022-06-15Added 23 answers

Step 1
Assume that f 0 and f C ( 0 , 1 ) and let F C 0 ( 0 , 1 ) be its anti-derivative, assume further that 0 1 f ( x ) d x > 0 , then for some large N, we have F ( x ) = 0 for all x ( 0 , 1 / N ) ( 1 1 / N , 1 ). Now express F ( x ) = a x f ( t ) d t for some a ( 0 , 1 ).
Step 2
And we know that 1 / n 1 1 / n f ( t ) d t 0 1 f ( t ) d t as n , find some M > 0 large enough such that 1 / M ( 0 , 1 / N ) and 1 / M < a, and that 1 / M 1 1 / M f ( t ) d t > 0 , then 1 / M 1 1 / M f ( t ) d t = 1 / M a f ( t ) d t + a 1 1 / M f ( t ) d t = F ( 1 / M ) + F ( 1 1 / M ) = 0 , , a contradiction, so F cannot be compactly supported.
Sonia Gay

Sonia Gay

Beginner2022-06-16Added 7 answers

Explanation:
The antiderivative of f C ( I ) is also in C ( I ). It is not in C c ( I ) (even if f C c ( I )) unless I f = 0.

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