Suppose X , Y are real-valued random vectors. When can we say E [ g ( X

Yahir Tucker

Yahir Tucker

Answered question

2022-06-14

Suppose X, Y are real-valued random vectors. When can we say E [ g ( X , Y ) | X ] is an a.e. continuous function in X? I have mostly convinced myself of this argument, save for one step where I want to argue E [ 1 n i = 1 n X i X i e i 2 | ( X 1 , . . . , X n ) ] p E [ E [ X i X i e i 2 ] | ( X 1 , . . . , X n ) ] = E [ X i X i e i 2 ] by appealing to the weak law of large numbers and the continuous mapping theorem.

Answer & Explanation

Donavan Scott

Donavan Scott

Beginner2022-06-15Added 22 answers

The error is e i = Y i X i β and model assumptions include ( X i , Y i ) iid and finite fourth moments of X i , Y i . Then the claim can be shown without appealing to the continuous mapping theorem since
E [ 1 n i = 1 n X i X i e i 2 | ( X 1 , . . . , X n ) ] = 1 n i = 1 n X i X i E [ e i 2 | ( X 1 , . . . , X n ) ] = 1 n i = 1 n X i X i E [ e i 2 | X i ] ( ( X i , Y i )  iid ) p E [ X i X i E [ e i 2 | X i ] ] ( WLLN ) = E [ E [ X i X i e i 2 | X i ] ] = E [ X i X i e i 2 ] ( LIE )

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?