How to find instantaneous rate of change for y ( x ) = 1 x +

Quintin Stafford

Quintin Stafford

Answered question

2022-06-14

How to find instantaneous rate of change for y ( x ) = 1 x + 2 at x=2?

Answer & Explanation

plodno8n

plodno8n

Beginner2022-06-15Added 17 answers

The instantaneous rate of change of y(x) at x = 2 is y'(2)
Express y ( x ) = 1 x + 2 = ( x + 2 ) 1
differentiate using the chain rule
y ( x ) = ( x + 2 ) 2 d d x ( x + 2 )
y ( x ) = ( x + 2 ) 2 = 1 ( x + 2 ) 2
y ( 2 ) = 1 ( 4 ) 2 = 1 16

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