Finding <munder> <mo movablelimits="true" form="prefix">lim <mrow class="MJX-TeXAtom-O

Brunton39

Brunton39

Answered question

2022-06-15

Finding lim n sin ( π n + 2 π log ( n ) n ) n log ( n ) sin ( π n )

Answer & Explanation

Braylon Perez

Braylon Perez

Beginner2022-06-16Added 34 answers

First,
lim n sin π n 1 n = π ,
so you might as well calculate
lim n sin ( π n + 2 π log ( n ) n ) log n .
You have
| sin ( π n + 2 π log ( n ) n ) log n | 1 log n           0 ,
so the limit is zero.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?