How to solve <munder> <mo movablelimits="true" form="prefix">lim <mrow class="MJX-TeXA

Ayanna Trujillo

Ayanna Trujillo

Answered question

2022-06-16

How to solve lim x 1 ln ( x ) x 1 using pre-derivative calculus?

Answer & Explanation

Ryan Fitzgerald

Ryan Fitzgerald

Beginner2022-06-17Added 17 answers

Hint: set x = e y ; if x 1, then y 0. The limit is a fundamental one.
xonycutieoxl1

xonycutieoxl1

Beginner2022-06-18Added 7 answers

Let me show you one more answer. Defining u = x 1, your limit becomes:
L = lim u 0 ln ( u + 1 ) u = 1 ,
since ln ( u + 1 ) behaves like u as u 0, indeed ln ( u + 1 ) u as u 0
Cheers!

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