Graph the solution set for the of linear inequalities y<1/3x+1y>=1/3x-2

Graph the solution set for the of linear inequalities
$y<\frac{1}{3}x+1$
$y\ge \frac{1}{3}x-2$

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Derrick

Step 1
We make tables for the auxiliary equations.
Step 2
Then we plot the points and graph the lines. then we shade the region depending on the inequalities. (0,0) means x=0 , y=0 satisfies both inequalities. 0<1 and $0\ge -2$
$y<\frac{1}{3}x+1\to 0<\frac{1}{3}\left(0\right)+1\to 0<1$
$y\ge \frac{1}{3}x-2\to 0\ge \frac{1}{3}\left(0\right)-2\to 0\ge -2$
For $y<\left(\frac{1}{3}\right)x+1$ we draw dotted line because strict inequality.
For $y\ge \left(\frac{1}{3}\right)x-2$ we draw solid line because equality holds.
For both shaded towards (0,0)