Consider a position measurement that is prone to a random error in any direction. This would mean th

Celia Lucas

Celia Lucas

Answered question

2022-06-08

Consider a position measurement that is prone to a random error in any direction. This would mean that the position would be in a circle where the probability curve taken across the diameter would show a normal distribution.
How can the probability be calculated that the position measurement is inside another circle?
I can ignore the cases where the circle of probability is entirely inside the detection circle (because the probability of being in the detection circle has reached 100%) and when it is entirely outside the detection circle (probability falls to 0%), i.e. the cases where the two circles do not intersect.

Answer & Explanation

Layla Love

Layla Love

Beginner2022-06-09Added 29 answers

If you have equal normal errors in x and y, you get a Rayleigh distribution. The probability distribution function in r is f ( r , σ ) = r σ 2 exp ( x 2 σ 2 ). Because of the factor r it is analytically integrable.

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