# Verify this triganomic identity you can only use 1 side to solve (cosx-tanx)/(sinx+cosx)=cosx-secx

Verify this triganomic identity you can only use 1 side to solve $\frac{\mathrm{cos}x-\mathrm{tan}x}{\mathrm{sin}x+\mathrm{cos}x}=\mathrm{cos}x-\mathrm{sec}x$
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First we need to check the identity. Let x=0 then:
$\frac{1-0}{0+1}=1-1$, which isn’t true because $1\ne 0$, so the identity is false.
To confirm, let $x=\frac{\pi }{4}:$

Therefore the identity has been wrongly stated. So the identity is actually an equation which has particular solutions for x. An identity has to be true for all x.